solve the differential equation dy/dx = sec(y-x)
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well first thing you need to kno is the derivative of sec which is 1/cos

for this problem you need to apply the dreaded chain rule. f'(g(x)) x g'(x)

 

the answer is

 1/cos(y-x) x derivative of inside which is just y prime or y' (derivative of x is just 1) (note that the derivative of y is y prime only when your taking the derivative with respect to y but in this problem you are taking the derivative with respect to x)

1/cos(y-x) x y
by Level 6 User (15.3k points)

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