8=3^7x-1
I am taking this as
. If this assumption is not correct, please tell me and i will correct the answer.
Taking logs of both sides of this, using log base 10, gives =log(3^{7x-1}))
Using log laws, this can become
=log(3)\cdot%20(7x-1))
Dividing both sides by log 3 gives
}{log(3)}=7x-1)
Then, simply divide both sides by 7 then add 1 to both sides to become /log(3)}{7}+1=x%20\approx%201.270%20(4sf))