How do you solve for "x" in this equation: 2x^2+16x-42

I really need help. I'm stumped. Thanks. frown

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1 Answer

You can't.  It has to be equal to something.  y = 2x^2 +16x -42, 0 = 2x^2 +16x -42, something.
by Level 13 User (103k points)

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