y=2x+2,(3,2) as a parallelline
A line parallel to the one specified would have
the same slope, 2. All we need is the intercept, b.
We are given one point that will satisfy the equation,
(3,2), so we can use y = mx + b to find a new b.
y = mx + b
b = y - mx
b = 2 - (2 * 3)
b = 2 - 6
b = -4
The equation for the new line is
y = 2x - 4