log(base x) 20+log(base x) 2

3log(base 3)p-1/2log(base 3) Q

2log(base 10)-3log(base 10)y

1-3log(base 3) x
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2 Answers

log(20)+log(2)=log(2*20) =log40....yukan yuze NE legal base for the log

### 3*log(p)=log(p^3)

(1/2)log(q)=log(root(q))

so 3log(p) -(1/2)log(q)=log[p^3/root(q)]...log tu NE base
by
log_x(20)+log_x(2)=log_x(20.2)=log_x(40)
by
edited

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