sin x = sq root of 3 times cos x find x

dont know how to solve, asked in our quiz a while ago(3/4/13)
in Trigonometry Answers by Level 1 User (360 points)

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1 Answer

sine(x)=root(3)*kosine(x)

sine^2(x)=3*kosine^2(x)

but, sine^2+kosine^2=1, so sine^2=1-kosine^2

1-kosine^2(x)=3*kosine^2(x)

4*kosine^2(x)=1

kosine^2(x)=1/4

kosine(x)=1/2=0.5

x=60 deg
by

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