factor 8x^3-8x

Question

How to factor 8x^3-8x

Answer 1

You can factor an 8x out of each term.  

8x^3 - 8x

Factor the 8x out and put it in front of brackets:

8x(  )

Now divide each term by the 8x.

8x(8x^3 / 8x - 8x/8x)

This leaves you with:

8x(x^2 - 1).

x^2 -1 is the difference between two perfect squares which factors out like this:

8x(x -1)(x+1)

To check your work, multiply the binomials using FOIL method then distribute the 8x back through the binomial and you should end up with your original problem.