Chicken and cow legs

There are 28 chickens and cows on a farm.

If the total no of cows' legs is 40 more than the total no of chickens' legs, find the no of chickens.
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2 Answers

28 anamals, so x+y=28

num chicken legs=2*x

num kow legs=num chiken legs+40,

so num kows=[(num chikens)/2] +10...y=(x/2)+10

x+(x/2)+10=28

1.5x=20-10=18

x=18/1.5=12

y=28-12=16.....12 chickens & 16 kows

24 chik legs, add 40=64 kow legs  & 64/4=16 kows
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