how do i solve x squared-5x=14
x² - 5x = 14
add (-14) into the left & right side of the equation
x² - 5x -14 = 14 - 14
14 cansel
x² - 5x -14 = 0
x² - 5x -14 = 0 is in the form of x² - dx - c = 0 ← quadratic equation
the nest step is by factoring
this will be in the form (x ± a)(x ± b)
where a&b whos product is c
and also the algibric sum is → a ± b = d
where our c = -14 and can be broken in to the following
a x b = c → what number a & b will give a product of -14
2 x 7 = +14 or -2 x 7 = -14 or -2 x (-7) = +14 or 2 x (-7) = -14
AND the algibric sum
a + b = d → what will be the sum of a & b that give us -5
-2 + 7 = 5 0r 2 + 7 = 9 or -2 + (-7) = - 9 or 2 + (- 7) = -5
So our factor to x² - 5x - 14 = 0
(x + 2)(x - 7) ◄ Ans