Question

find the sum of all those integers between 99 & 800 each of which on division by 16 leaves the remainder 7

Answer 1

??????????? yu wanna get sum, then divide bi 16 ???????

integers tween 99 & 800

???? duit inklude 99 & 800???

sum av all integers INKLUDING 99 & 800=315,549

yu hav 702 numbers

averaej=(start+end)/2=(99+800)/2=899/2=449.5

sum=n*averaej=702*449.5=315,549

then divide bi 16, yu get19721.8125

#### if yu want numbers tween, thats 100 thru 799

n=700 numbers, averaej=449.5, sum=314,650