solve for x when (.182+x)/(.106-2x)=3.24
Im trying to solve for x its for a chemistry equation
but i need to solve for x using the quadratic equation
and i dont know which equals a b and c to find x.
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You can't solve this with the quadratic formula,
because there is no x^2 term. Observe:
(.182+x)/(.106-2x)=3.24
Multiply both sides by (.106-2x) to eliminate the
fraction on the left.
(.106-2x) * (.182+x)/(.106-2x) = (.106-2x) * 3.24
0.182 + x = 0.34344 - 6.48x
This is a linear equation. Even if you arranged it
so that all the terms are on the left, leaving a zero
on the right side, you still would not have an x^2 term.
That means that the "a" coefficient would be zero.
When you try to use that in the quadratic formula, the
denominator would be 2a = 2 * 0 = 0. You cannot
divide by zero, so you are now stuck, with no possible
solution.
If you solve the equation from where I have taken it,
you will find the value of x.
0.182 + x = 0.34344 - 6.48x
6.48x + x = 0.34344 - 0.182
7.48x = 0.16144
(Note that you could now subtract 0.16144 from both sides
to get 7.48x - 0.16144 = 0, but you still don't have an x^2
term, so a=0, b=7.48 and c=-0.16144. That pesky 0 for the
value of a will give that 0 denominator. Impossible to divide.)
x = 0.0215828877