3sinB+6=5sinB+7

Question

It just says that and that B (beta) is more than or equal to 0 degrees but less than or equal to 360 degrees.

Answer 1

3sinB+6=5sinB+7
It just says that and that B (beta) is more
than or equal to 0 degrees but less than or
equal to 360 degrees.

3sinB + 6 = 5sinB + 7
3sinB + 6 - 5sinB = 5sinB + 7 - 5sinB
-2sinB + 6 - 6 = 7 - 6
-2sinB = 1
-2sinB / -2 = 1 / -2
sinB = -1/2

Here, we find that the problem statement
is wrong. In order for the sine of an angle
to be negative, the angle has to be negative,
i.e., it is LESS than 0.

B = arcsin(-1/2) = -30 degrees

The sine of +30 degrees is +0.5