express in lowest terms 9x-18 over 3x^2-12

I have to express it in lowest terms but i dont really understand how to do so.
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1 Answer

(9x-18) / (3x^2 -12)

=9(x-2) / [3*(x^2-4)]

=(9/3)*(x-2) / [(x-2)*(x+2)]

=3 / (x+2)
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