solve:- 2xz+yz+4x+2y / 2z+4

2xz+yz+4x+2y / 2z+4
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1 Answer

Is that -2xz or 2xz at the beginning?

If it's 2xz then:

(2xz + yz + 4x + 2y) / (2z + 4)

( (2x + y)z + 2(2x+y) ) / 2(z + 2)

(z + 2)(2x + y) / 2(z + 2)

(2x + y) / 2

x + y/2
by Level 13 User (103k points)

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