hcl acid solutions

A chemist mixes 11% hcl acid with 6% hcl solution. How many ml of each solution should be used to make 600ml solution that is 8% hcl
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1 Answer

asid...want 600 ml av 8%

hav 6% & 11% on hand

8% av 600=0.08*600=48

x +y =600   or y=600-x

0.06x + 0.11y=48

0.06x +0.11*(600-x)=48

0.06x -0.11x +66=48

-0.05x=48-66 =-18

x=18/0.05

x=360

y=600-x=600-360=240
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