log(8)(t+10) - log(8)(t-1) = log(8)12

how do i solve this math problem
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1 Answer

log8 (12)= 1.1949875002

log(x+10) - log(x-1) same as

log [(x+10)/log(x-1)]= log(12)

thus, (x+10)/(x-1)=12

x+10=12*(x-1)   =12x -12

x-12x=-12 -10

-11x=-22

x=2

x+10=12 & x-1=1, so (x+10)/(x-1)=12
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