Which of the ordered pairs satisfy the following equation?    y=2/3x

(14,21)

(42,28)

(21, 3/2)

(21,14)

(7,14)

(28,42)
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

y = (2/3)x

In (21,14), x = 21 and y = 14, 
to be a solution, it must be a true statement,
once you substitute the values in for x and y


y = (2/3)x
14 = (2/3)(21) {substituted 21 in for x and 14 in for y}
14 = 14 {multiplied 2/3 by 21}

That is a true statement, therefore
(21,14) is a solution to y = (2/3)x
www.algebrahouse.com

by Level 4 User (8.4k points)

 

y = (2/3)x 

In (42,28), x = 42 and y = 28,  
to be a solution, it must be a true statement, 
once you substitute the values in for x and y
 

y = (2/3)x 
28 = (2/3)(42) {substituted 42 in for x and 28 in for y} 
28 = 28 {multiplied 2/3 by 42} 

That is a true statement, therefore 
(42,28) is a solution to y = (2/3)x 

by

Related questions

1 answer
asked Jul 11, 2012 in Algebra 1 Answers by anonymous | 1.6k views
1 answer
asked Feb 28, 2013 in Pre-Algebra Answers by anonymous | 3.6k views
0 answers
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,216 users