How do I work this problem out?

Question

(x)/(x-2) + (6)/(x+3) / (3)/(x+3)-(x)/(x-2)

Answer 1

How do I work this problem out?

TRY TO WORK ON THE NUMERATOR : LCD = (x+3)(x-2)

(x² + 3x) + (6x - 12) /(x+3)(x-2) / (3)/(x+3)-(x)/(x-2)

(x² + 9x - 12) /(x+3)(x-2) / (3)/(x+3)-(x)/(x-2)

TRY TO WORK ON THE DENAMERATOR: LCD = (x-2)(x+3)

(x² + 9x - 12) /(x+3)(x-2) / (3)(x-2)-(x)(x+3) /(x-2)(x+3)

(x² + 9x - 12) /(x+3)(x-2) / (3x-6- x²-3x) /(x-2)(x+3)

(x² + 9x - 12) /(x+3)(x-2) / (-6- x²) /(x-2)(x+3)

(x² + 9x - 12) /(x+3)(x-2) / -( x²+6) /(x-2)(x+3)

reverse the numerator & the denamerator in the denamertor side then multiply

[(x² + 9x - 12) /(x+3)(x-2)]  multiply [(x-2)(x+3) / -( x²+6) ]

(x+3)(x-2) Will cancel out

[(x² + 9x - 12) /1 ] multiply [1 / -( x²+6) ]

(x² + 9x - 12)  / - ( x²+6)  ◄ Ans

Answer 2

36-6*2