the value of x^2-6x+13 can never be less than

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1 Answer

y=x^2 -6x +13

dy/dx=2x-6

set tangent=0...2x=6, so x=3

slope=0 is horizontal line= top or bottom

This equashun go up, so yu get bottom

y at x=3...9-18+13=4

yukan chek...at x=0, y=13...hier up
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