200=(0.05v*0.05v)+2.2v

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anonymous · Answer 1 · 2013-01-31T14:50:17+0000

(0.05x)^2 +2.2x -200=0

or 0.0025 x^2 +2.2x -200=0

or 25x^2 +22000x-2000000=0....thats 2*10^6

x=83.0678732 or -963.0678732, from quadratik equashun

-b/2a=-440

b^2 -4ac=684000000, & root=26153.39366124

anonymous · Answer 2 · 2013-03-10T21:50:59+0000

je veu résoudre un calcul et nous a di de le mettre sou forme d'une équation 71200/0.05

200=(0.05v*0.05v)+2.2v

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