f(x)=x3/3 -3x....?

Question

horizontal tangenst of a cubic polinomial

Answer 1

tangent=dy/dx...slope av the kerv

for y=ax^3, dy/dx=3ax^2

tu tri find lo or hi av y, look for x weer dy/dx=0...weer slope=0

in this kase, 3ax^2=0 at x=0