3x + 4y - 12 = 0
to find the x- intercept,
let y= 0
So, 3x + 4y - 12 = 0
substitute the value y;
3x + 4 (0) - 12 = 0
3x + 0 - 12 = 0
3x = 0 + 12
3x/3 = 12/3
x = 4, the x- intercept is 4 ---- the ordered pair is (4, 0).
To solve for the y- intercept, let x = 0
3x + 4y -12 = 0
3(0) + 4y -12 = 0
0 + 4y - 12 = 0
4y = 0 + 12
4y = 12
4y/4 = 12/4
y = 3 , therefore, 3 is the y-intercept and the ordered pair is ( 0,3)