sinA+SinB/cosA+cosB=tan (A/2+B/2)

sinA+sinB (A+B) ------ = tan ---- cosA+cosB 2 I really need to figure out this identity! If someone could help that would be great! BTW the (A+B) is ontop of the two and the tan is to the left of it untouched.
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1 Answer

sinA +sinB/cosA+cosB =2sin(A+B)/2cos(A-B)  /  2cos(A+B)/2cos(A-B)/2

                                    = sin(A+B)/2 / cos(A+B)/2

                                      = tan(A+B)/2

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