2x^3-25x^2+82x-35=0 given that 5 is a zero of f(x)=2x^3-25x^2+82x-35

How do you solve this equation using synthetic division?
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1 Answer

divide: (2x^3 -25x^2 +82x -35) / (x-5)

giv 2x^2 -15x+7

this become (x-7)(x-0.5)

so original=(x-5)*(x-7)*(x-0.5)
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