how do you graph y=-2x^2-4x+3

I need to graph parabolas in standard, vertex and intercept form.
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1 Answer

y=-2x^2 -4x+3

-2x^2 tell yu it go down

the zeroes=-2.5811388 & 0.5811388=weer it hit x-axis

dy/dx=4x-4, so tangent=0 at x=+1...the top av the parabola...(1.-3)
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