how to solve for x: 7^(5x) = 9^(3x-1)

solve for x using logarithms or natural log
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1 Answer

7^5x =9^(3x-1)

log(7^5x)=5x*log(7)

log[9^(3x-1)] =(3x-1)*log(9)

so 5x*log(7)=(3x-1)*log(9)

or 5x/(3x-1)=log(9)/log(7)=0.954242509 / 0.84509804 = 1.129150068

or 5x=1.129150068*(3x-1)

5x=3.387450203x -1.129150068

1.612549797x=-1.129150068

x=-1.129150068/1.612549797

x=-0.700226479
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