fourier series of function f(x)=cos^2x

Differential equations :

fourier series of the function f(x)=cos^2x

hint : the function is even with period pi,

L= pi/2
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1 Answer

cos^2(x) can be written as 1/2 + 1/2*cos(2x). So A0=Ak=1/2, Bk=0 and Ck=1/2*Ak = 1/2 * 1/2 = 1/4.
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