mixed numbers and improper fractions
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7 Answers

aent no such thang as "improper frakshun"

all frakshuns R frakshuns or not

3 1/5=3.2

& thats NOT
by
no such thing as an 'improper frakshun', but there is such thing called 'improper fraction'.
SO U HAVE 3 1/2, FIRST TAKE THE DENOMINATOR (2) MULTIPLY IT BY THE WHOLE NUMBER (3) ULL GET 6 THEN ADD THE NUMBERATOR (1) AND ULL HAVE 7. WRITE THE 7 AS A NUMBERATOR AND PLACE THE ORIGIONAL DENOMINATOR (2) BACK IN ITS PLACE SO ULL HAVE 7/2 IS THE IMPROPER FRACTION. TO CHE UR WORK JUST DIVIDE THE NUMBERATOR BY THE DENOMINATOR:     7/2----2 GOES INTO 7, 3 TIMES WITH 1 LEFT OVER, THAT LOOKS LIKE 3 1/2
by
You do 5x3 and get 15. Then you would add 1 because that is the numerator. Ane your improper fraction should be 16/5.
by

1=5/5

5/5x3=15/5

15/5+1/5=16/5

by Level 9 User (42.6k points)
31/5
by

16/5


3 * 5 + 1

by Level 3 User (2.6k points)

I assume the question would be: Turn the mixed number 3 (1/5) {or 3 and (1/5)} into the improper fraction equivalent.

My answer: A mixed number consists of an integer(ex. 3) and a fraction(ex. 1/5) or a decimal(ex. 0.2).  While, a improper fraction is a fraction in which the numerator is greater than or equal to the denominator.  Notice that 3 (1/5) does not mean multiplying 3 times (1/5), but means 3+(1/5).

The first step in adding or subtracting of fractions is converting every term in the equation into the equivalent fractions with common denominators.  In order to make the denominator minimal for easier handling, we'll use LCM(Least Common Multiple) of its denominators. 

The denominators for 3 and (1/5) are 1 and 5 respectively, because 3+(1/5)=(3/1)+(1/5). Since 1 and 5 have no common factors, the LCM of 1 and 5 is 1*5=5.  

So, 3 (1/5) is rewritten: 3 (1/5)=3+(1/5)=(3/1)+(1/5)=(1/1)*(3/1)+(1/5)=(5/5)*(3/1)+(1/5)=(5*3)/(5*1)+(1/5)=(15/5)+(1/5)=(15+1)/5=(16)/5.  We have: 3 (1/5)=(16)/5.  

Answer: the improper fraction for the mixed number 3 (1/5) is (16)/5.    

by

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