ADDITION 27 AND 19 using BCD method

Addition 27 and 19 using BCD method .could you have answer in step by step method.
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Initially the 144.74 and 19 ohms are each 163.74 so the initial resistance is 

163.74 / 2 = 81.87 ohms 

the initial current is E / (81.87+R) 

With the switch closed the the 144.74 and 19 ohms are in parallel. 

Their combination is 19*144.74/(19 + 144.74) = 16.795 ohms 

Two of these combinations are in series so the current is E / (33.59057 + R) 

For the current to double 

E / (33.59057 + R) = 2 * E / (81.87+R) 

1 / (33.59057 + R) = 2 / (81.87+R) 

2 (33.59057 + R) = (81.87+R) 

67.18114 + 2R = 81.87 + R 

R = 81.87 - 67.18114 = 14.68886 ohms

 

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