How do I work this problem? (2x^4y^7)^2  (x^6y1)^-3

Thank you, Lashay
in Algebra 2 Answers by Level 1 User (120 points)

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2 Answers

(2x^4 y^7)^2=4x^8*16y^14

=(4*16)*x^8y^14

=64 x^8y^14

>>>>>>>>>

(x^6y1)^-3=1 / [(x^18)(y1^3)]
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How do I work this problem out 3.2n - 2n-2 over 2n+1
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