if log a=2 and log b=3 what is the numerical value og log(√a/b^3

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1 Answer

log[ root(a)*b^-3]=log(root(a)) + log(b^-3)

=(1/2)log(a) -3*log(b)

log(a)=2 & log(b)=3

yu get (1/2)*2 -3*(3)

=1-9

=-8
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