graph of 2^-x

Question

given g(x)=2^-x on [1/3,1] how to solve it by fixed point iteration??

Answer 1

2^-x:

wen x=0, yu hav 2^0=1

wen x=1, 2^-1=1/2=0.5

bigger x get, kloeser it come tu zero

for negativ x, yu hav 2 raesed tu positiv power, so it get bigger the farther yu

go from x=0

2^-1/3=1/x^1/3, thats 1/kube root(2)=1/1.25992105=0.793700525

Answer 2

shut up america