the solution to 5x-5=-10 7x-2y+4=6 3x+2y=-82

Question

I'm not sure what category the answer would be in....feel free to more the question to a more appropriate category

Thanks,

Sharlene

Answer 1

???? 3 strate lines ???

??? maebee it make a triangel ???????

line 1...???5x-5=-10, me spekt that spozed tu be 5x-5y=-10 or 5y=5x+10 become y=x+2

...strate line slope=1 (angel=45 deg) go thru (0,2)

line 2...7x-2y+4=6...become 2y=7x -2, or y=3.5x-1...slope=3.5 & go thru point=(0,-1)

line 3...3x+2y=-82, or 2y=-3x-82...y=-1.5x -41...go thru point=(0,-41)

Answer 2

the solution to 5x-5=-10  7x-2y+4=6  3x+2y=-82

I'm not sure what to do with the first equation.
5x - 5 = -10
5x = -10 + 5 = -5
x = -5 / 5 = -1
If that identifies a line, it is a vertical line located one step to the left
of the y axis.

However, the two remaining equations can be solved simultaneously.

Equation 2:
7x-2y+4=6
7x - 2y = 2

Now, we add equation two and equation three to eliminate the y term:

7x -  2y =   2
3x + 2y = -82
-------------------
10x       = -80
10x = -80
x = -8

With that, we can use equation three to solve for y:
3 * (-8) + 2y = -82
-24 + 2y = -82
2y = -28
y = -24

You can verify by using equation two, but what we have
is a point where two straight lines, specified by equations
two and three, intersect on a graph.

(-8, -24)