2312/567-1=[r/12]^36

i am in math 142 and this is as far as i got into the problem im not sure how to get rid of the r or how to solve for it IF that IS the next step....
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1 Answer

 

[2312 / 567] - 1 = [r / 12]^36
1745 / 567 = [r / 12]^36
[1745 / 567]^(1/36) = r / 12
1.031719062 = r / 12
r = 12(1.031719062)
r = 12.38062875

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