how do you solve 3ln(5x+6)=21

i'm not sure how to solve a natural log with a coeffient other than one in front
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1 Answer

3 ln(5x+6)=21

ln(5x+6)=7

e^ln=1, so 5x+6=e^7

5x=e^7-6

x=(e^7-6)/5

e^7=1,096.63315854

e^7-6=1090.63315

xxx/5=218.12663
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