how do i figure out how long it will take?
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2 Answers

start $=7,500$, want=14,000$, kompound daely at 0.01%

end/start=14000/7500=1.86666666

(end/start)=[1+%/n]^nt

n=365 daes/yeer

0.01%=0.0001

%/365=0.0001/365=0.0000002739726

(1.00000027397)^365t=1.866666

take log av both sides...365t*log(1.0000002739)=log(1.86666)

t=(1/365)*log(1.8666)/log(1.0000002739)

log(1.0000002739=0.99999911856

1/log(1.000002739)=8434378.8

log(1.8666)=0.2710666

0.2710666*8434378.8=2286278

2286278/365=6,264 yeers
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mistipe...log(1.0000002739)=0.00000011856
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