if 9 similar coins are given and says one among this coin is having weight difference either more or less. with three chances of weighing how can you find the coin which is having difference in weight and this is more or less.
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1 Answer

assume yu hav a balans skale,

1. put 3 koins in 1 pan & 3 in other pan.

2. if pan balans, bad koin not in this bunch av 6 koins...tri the other 3

from other 3, put 1 koin in 1 pan & 1 in other pan.

If it balans, bad koin is the 1 koin yu did NOT put in a pan.

If it dont balans in step 1 or 2, 1 koin in 1 pan is bad, but yu dont no wich.

Take 3 koins from 1 pan & split it intu ...like step 2 & maeby 1 pan hevee or not

Problem...if yu dont no if bad koin is hevee or lite, yu kant be shuer after 3 steps

take xtra step the chek that.
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