how to solve log8/log12-log3

log8/log12-log3
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1 Answer

Log8=log2^3=3log2

log 12 = log(3 X 2^2)
=log(2^2) + log 3
=2log 2 + log 3

3log2/2log2+log3-log3

=3log2/2log2

=3/2

=1 ½
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