Solve the Right triangle given that A = 50 degrees, C = 90 degrees, and a = 13 meters.
The triangle is labelled ABC.
A = 50, C = 90, therefore B = 40 degrees.
From Trig, cos(40) = BC/AB = a/AB
AB = a/cos(4) = 13/xos(40) = 16.97
AB = 16.97 m
By Pythagoras,
AC^2 = AB^2 - AC^2
AC^2 = 16.97^2 - 13^2
AC^2 = 118.99
AC = 10.908 m