how do you solve square route of 108X to 7th power y to 2nd power

we are simplifing radicals and I am just not getting it.
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1 Answer

square root(108x^7y^2)

=square root[(3^3)(2^2)(x^7)(y^2)]

=3*2*x^3*ysquare root(3x)

=6x^3*y square root(3x)
by Level 8 User (32.3k points)

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