Can someone help me with this please?
asked May 28, 2012 in Trigonometry Answers by anonymous

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:

To avoid this verification in future, please log in or register.

1 Answer

Draw a right-angled triangle ABC where B is 90 deg, A is theta. cot(theta)=AB/BC=7. AC=sqrt(7^2+1)=5sqrt(2). AB=7, BC=1.

sin(theta)=BC/AC=1/5sqrt(2)=0.2sqrt(2)/2=0.1sqrt(2)=0.1414. cos(theta)=7/5sqrt(2)=1.4sqrt(2)/2=0.7sqrt(2)=0.9899.

sec(theta)=1/cos(theta)=5sqrt(2)/7=1.0102. These are all approximate values and apply to quadrant 1. cot(theta)=7/1  in quadrant 1, or -7/-1 in quadrant 3. In this quadrant sin, cos, sec are all negative, so sin(theta)=-0.1414, cos(theta)=-0.9899, sec(theta)=-1.0102 in QIII, and 0.1414, 0.9899, 1.0102 in QI.

answered Sep 5, 2015 by Rod Top Rated User (501,520 points)
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
80,289 questions
84,162 answers
2,066 comments
67,174 users