solve for x, 0 < or equal to x < or equal to 2pi: a. 2 sin x- square root,3 =0

Question

solve for x, 0 < or equal to x < or equal to 2pi:

a. 2 sin x- square root of 3 =0

b. 1/sin^2x = 4

Answer 1

2 sin x- square root of 3 =0

2sinx = sqrt3

sinx = sqrt3/2

x = 60 degree, sin 60 = sqrt3/2

1/sin^2x = 4

sin^2x = 1/4

sinx = sqrt(1/4)

sinx = 1/2

x = 30 degree, sin 30 = 1/2