algebra problems

The perimeter of a rectangle is 18 feet the length is 5 feet longer than the width find the dementions write a system of linear equations and solve the resulting system. let x be the length and y be the width

the first equation

2x + 2y =

the second equation

x = y+
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1 Answer

The perimeter of a rectangle is 18 feet the length is 5 feet longer than the width find the dementions write a system of linear equations and solve the resulting system. let x be the length and y be the width

the first equation

2x + 2y =18

the second equation

x = y+ 5

2(y + 5) + 2y = 18

4y + 10 = 18

4y = 18 -10 = 8

y = 4/2=2

x = 5+ 2 = 7

by Level 8 User (36.8k points)

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