lcm of (x+4)(x+2) and(x-2)(x+2)
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What is the LCM of (x+4)(x+2)and(x-2)(x+2)

Let M = (x+4)(x+2), and let N = (x-2)(x+2)

Take out the common factor of (x+2)

This gives us,

M= F*(x+4), and N = F*(x-2)

Then lcm(N,N) = F*lcm((x+4), (x-2)) = F*{(x+4)*(x-2)}

lcm = (x+2)(x+4)(x-2) = (x+4)(x^2 - 4)

Answer: lcm = (x+4)(x^2 - 4), where (x+4) and (x-2) are coprime.

by Level 11 User (81.5k points)

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