What is the LCM of (x+4)(x+2)and(x-2)(x+2)
Let M = (x+4)(x+2), and let N = (x-2)(x+2)
Take out the common factor of (x+2)
This gives us,
M= F*(x+4), and N = F*(x-2)
Then lcm(N,N) = F*lcm((x+4), (x-2)) = F*{(x+4)*(x-2)}
lcm = (x+2)(x+4)(x-2) = (x+4)(x^2 - 4)
Answer: lcm = (x+4)(x^2 - 4), where (x+4) and (x-2) are coprime.