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We can eliminate “m”, and we are left with “s” and its permutations with “p”, “r” and “i”. This gives us:

s; sp, sr, si, ps, rs, is; spr, spi, sir, and all the permutations of these; spri and all its permutations.

There are 6 each of the 3-letter permutations.

When we add all these together we get: 1+6+3×6+24=1+6+18+24=49.
by Top Rated User (906k points)

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