The complete question is The diameter of a copper (Cu) atom is roughly 1.3 x 10^-10 m. How many times can you divide evenly a piece of 10-cm copper wire until it is reduced to two separate copper atoms? (Assume there are appropriate tools for this procedure and that copper atoms are lined up in a straight line, in contract with each other.) Solution wt explanation. TIA!
in Other Math Topics by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The width of two Cu atoms is 2.6×10⁻¹⁰m=2.6×10⁻⁸cm.

We need to divide 10cm by this to find out how many times the copper wire needs to be divided:

10÷(2.6×10⁻⁸)=10x10⁸/2.6=3.8462×10⁸=384,620,000 approx.

(If we were to halve the length of copper wire to 5cm, then halve again to 2.5cm, and so on, we would only have to do this between 28 and 29 times to get to the width of two atoms!)

by Top Rated User (610k points)

Related questions

Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
82,167 questions
86,657 answers
76,258 users