seperating the number 41 into three parts A, B and C ,we get A + B + C = 41
it will be B=2A and C=2A-4 plugging this to the above equation we get A+2A+2A-4=41
or 5A-4=41. --->>> 5A=41+4 --->>>. 5A=45 and A=45/5 so A=9 and B=2(9)=18 and C=2(9)-4
so C = 18-4=14 so A=9, B=18 and C=14 so A+B+C= 9+18+14=41