• I need your help
asked Jan 8 in Algebra 1 Answers by anonymous

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

seperating the number 41 into three parts  A, B and C ,we get A + B + C = 41

it will be B=2A and C=2A-4 plugging this to the above equation we get A+2A+2A-4=41

or 5A-4=41. --->>>  5A=41+4  --->>>.  5A=45  and A=45/5    so A=9  and B=2(9)=18  and C=2(9)-4

so C = 18-4=14   so A=9,  B=18 and C=14 so A+B+C= 9+18+14=41
answered Jan 8 by tadinn Level 5 User (13,160 points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
81,851 questions
86,191 answers
69,792 users