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asked Jan 8 in Algebra 1 Answers by anonymous

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seperating the number 41 into three parts  A, B and C ,we get A + B + C = 41

it will be B=2A and C=2A-4 plugging this to the above equation we get A+2A+2A-4=41

or 5A-4=41. --->>>  5A=41+4  --->>>.  5A=45  and A=45/5    so A=9  and B=2(9)=18  and C=2(9)-4

so C = 18-4=14   so A=9,  B=18 and C=14 so A+B+C= 9+18+14=41
answered Jan 8 by tadinn Level 5 User (13,160 points)

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