What is the absolute maximum for 2x^3-3x^2-5?

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What is the absolute maximum for 2x^3-3x^2-5?

​Let f(x) = 2x^3 - 3x^2 - 5

​f' = 6x^2 - 6x

Setting f' = 0,

​6x^2 - 6x = 0

6x(x - 1) = 0

x = 0, x = 1

​f(0) = 0 - 0 - 5 = -5

​f(1) = 2 - 3 - 5 = -6

​|f(0) = 5 and |f(1)| = 6

​So, absolute maximum of f(x) is 6

by Level 11 User (81.5k points)

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