Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
call the three consecituve even integers p,q r.
p = 2n, q = 2n + 2, r = 2n + 4
3p = 2q + 6 (three times the first integer is six more than twice the second integer)
3(2n) = 2(2n + 2) + 6
6n = 4n + 4 + 6
2n = 10
n = 5
p = 10
q = 12
r = 14