1is x ,2is x+2, 3is x+4
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Find three consecutive even integers such that three times the first integer is six more than twice the second integer?

​call the three consecituve even integers p,q r.


p = 2n, q = 2n + 2, r = 2n + 4

3p = 2q + 6        (three times the first integer is six more than twice the second integer)

​3(2n) = 2(2n + 2) + 6

6n = 4n + 4 + 6

2n = 10

n = 5

p = 10

q = 12

​r = 14

by Level 11 User (81.5k points)

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