Question

6 was added to some number. This sum was then multiplied by 6 and that product was then divided by 3 for a result of 4. What was the initial number?

Answer 1

6 was added to some number. This sum was then multiplied by 6 and that product was then divided by 3 for a result of 4. What was the initial number?

Let tne initial number be N.

​N + 6                      (6 was added to some number)

​(N + 6)*6                (This sum was then multiplied by 6)

(N + 6)*6 / 3           (that product was then divided by 3)

(N + 6)*6 / 3 ​= 4     (for a result of 4)

(N + 6)*2 = 4

N + 6 = 2

N = -4

Comments

please double check the value of N

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Originally had the answer as N = 4. Corrected now.